restructure section on physics
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@ -1375,14 +1375,37 @@ The speed restriction table for trains includes the speed limits for a train, wh
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\addcontentsline{toc}{part}{Appendices}
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\section{Physics}\label{s:physics}
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This section is mainly intended as a reference that is provided for convenience.
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\subsection{Train acceleration}
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\subsection{Movement}
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This section will use $x$ as the position and \( s = \Delta x \) as the distance.
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\begin{align*}
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v(T) &= v_0 + \int_0^T a(t) dt \\
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x(T) &= x_0 + \int_0^T v(t) dt \\
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s(T) &= \Delta x = \int_0^T v(t) dt
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\end{align*}
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\subsubsection{Constant acceleration}
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\begin{align*}
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v(T) &= v_0 + \int_0^T a(t)dt = v_0 + aT \\
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x(T) &= x_0 + \int_0^T v(t)dt = x_0 + v_0T + \frac{1}{2}aT^2 \\
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s(T) &= v_0T + \frac{1}{2}aT^2
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\end{align*}
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In certain cases, the starting velocity $v_0$ and the target velocity $v_1$ are known:
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\begin{align*}
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t &= \frac{v_1 - v_0}{a} \\
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s &= \frac{v_1^2 - v_0^2}{2a}
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\end{align*}
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\subsubsection{Acceleration of a train}
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The acceleration of a train is calculate as follows:
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\[a = a_{\text{all}} + a_{\text{locomotive}}\cdot\frac{n_{\text{locomotives}}}{n_{\text{wagons}}}\]
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Please not that slopes are not taken into consideration.
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With the following constants:
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\subsubsection{Acceleration constants}
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\begin{tabular}{|c|r|r|}
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\hline
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Lever & $a_{\text{all}}$ & $a_{\text{locomotive}}$ \\
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@ -1393,15 +1416,7 @@ With the following constants:
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$3$ & $0$ & $0$ \\
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$4$ & $0.5$ & $1.5$ \\
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\hline
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\end{tabular}\\
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Please note that, as shown in the equation above, slopes are not taken into consideration.
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The time needed to accelerate from $v_0$ to $v_1$ can be calculated as follows:
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\[ t = \frac{v_1-v_0}{a} \]
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The distance needed to accelerate from $v_0$ to $v_1$ can be calculated as follows:
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\[ s = \frac{v_1^2 - v_0^2}{2a} \]
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\end{tabular}
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\ifx\HCode\undefined
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\printindex
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